-5x^2=-195

Solution for -5x^2=-195 equation:

-5x^2=-195

We move all terms to the left:

-5x^2-(-195)=0

We add all the numbers together, and all the variables

-5x^2+195=0

a = -5; b = 0; c = +195;
Δ = b2-4ac
Δ = 02-4·(-5)·195
Δ = 3900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3900}=\sqrt{100*39}=\sqrt{100}*\sqrt{39}=10\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{39}}{2*-5}=\frac{0-10\sqrt{39}}{-10}
=-\frac{10\sqrt{39}}{-10}
=-\frac{\sqrt{39}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{39}}{2*-5}=\frac{0+10\sqrt{39}}{-10}
=\frac{10\sqrt{39}}{-10}
=\frac{\sqrt{39}}{-1}
$